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Factorise by taking out the common facto...

Factorise by taking out the common factors :
`2(2x - 5y)(3x + 4y) - 6(2x - 5y)(x-y)`

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To factorise the expression \( 2(2x - 5y)(3x + 4y) - 6(2x - 5y)(x - y) \), we can follow these steps: ### Step 1: Identify the Common Factor We can see that \( (2x - 5y) \) is a common factor in both terms of the expression. ### Step 2: Factor Out the Common Factor We can factor out \( (2x - 5y) \) from the expression: \[ 2(2x - 5y)(3x + 4y) - 6(2x - 5y)(x - y) = (2x - 5y) \left[ 2(3x + 4y) - 6(x - y) \right] \] ### Step 3: Simplify the Expression Inside the Brackets Now, we simplify the expression inside the brackets: \[ 2(3x + 4y) - 6(x - y) = 6x + 8y - 6x + 6y \] Combine like terms: \[ 6x - 6x + 8y + 6y = 14y \] ### Step 4: Write the Final Factored Form Now, substituting back into the factored form, we have: \[ (2x - 5y)(14y) \] ### Final Answer Thus, the expression \( 2(2x - 5y)(3x + 4y) - 6(2x - 5y)(x - y) \) can be factored as: \[ 14y(2x - 5y) \] ---
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