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Find, to the nearest rupee, the amount and the compound interest on 9000 for `1 (1)/(2)` years at 8% per annum, the interest being compounded half-yearly.

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To solve the problem of finding the amount and compound interest on ₹9000 for 1.5 years at an 8% annual interest rate compounded half-yearly, we can follow these steps: ### Step 1: Identify the given values - Principal (P) = ₹9000 - Time (T) = 1.5 years = \( \frac{3}{2} \) years - Rate (R) = 8% per annum - Since the interest is compounded half-yearly, we need to adjust the time and rate accordingly. ### Step 2: Adjust the time and rate for half-yearly compounding - The number of compounding periods per year = 2 (since it is compounded half-yearly). - Therefore, the total number of compounding periods (n) = \( 2 \times \frac{3}{2} = 3 \). - The effective rate per half-year = \( \frac{8}{2} = 4\% \). ### Step 3: Use the compound interest formula The formula for the amount (A) when interest is compounded is: \[ A = P \left(1 + \frac{r}{100}\right)^n \] Where: - \( P \) = Principal - \( r \) = Rate of interest per period - \( n \) = Number of compounding periods Substituting the values: \[ A = 9000 \left(1 + \frac{4}{100}\right)^3 \] ### Step 4: Calculate the amount First, calculate \( 1 + \frac{4}{100} = 1.04 \). Now substitute this back into the formula: \[ A = 9000 \times (1.04)^3 \] Calculating \( (1.04)^3 \): \[ (1.04)^3 = 1.124864 \] Now calculate the amount: \[ A = 9000 \times 1.124864 \approx 10123.776 \] ### Step 5: Round the amount to the nearest rupee Rounding \( 10123.776 \) gives us: \[ A \approx ₹10124 \] ### Step 6: Calculate the compound interest Compound Interest (CI) can be calculated using the formula: \[ CI = A - P \] Substituting the values: \[ CI = 10123.776 - 9000 \approx 1123.776 \] Rounding \( 1123.776 \) gives us: \[ CI \approx ₹1124 \] ### Final Results - Amount (A) = ₹10124 (to the nearest rupee) - Compound Interest (CI) = ₹1124 (to the nearest rupee)
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