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The sum of the length, breadth and height of a cuboid is 38 cm and the length of its diagonal is 22 cm. Find the surface area of the cuboid.

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To find the surface area of the cuboid given the sum of its dimensions and the length of its diagonal, we can follow these steps: ### Step 1: Define the variables Let: - Length = \( l \) - Breadth = \( b \) - Height = \( h \) ### Step 2: Set up the equations From the problem statement, we have two equations: 1. The sum of the length, breadth, and height: \[ l + b + h = 38 \quad \text{(Equation 1)} \] 2. The length of the diagonal: \[ \sqrt{l^2 + b^2 + h^2} = 22 \] Squaring both sides gives: \[ l^2 + b^2 + h^2 = 22^2 = 484 \quad \text{(Equation 2)} \] ### Step 3: Expand the square of the sum of dimensions We can use the identity: \[ (l + b + h)^2 = l^2 + b^2 + h^2 + 2(lb + bh + hl) \] Substituting Equation 1 into this identity: \[ 38^2 = l^2 + b^2 + h^2 + 2(lb + bh + hl) \] Calculating \( 38^2 \): \[ 1444 = l^2 + b^2 + h^2 + 2(lb + bh + hl) \] Now substitute Equation 2 into this equation: \[ 1444 = 484 + 2(lb + bh + hl) \] ### Step 4: Solve for \( lb + bh + hl \) Rearranging the equation gives: \[ 1444 - 484 = 2(lb + bh + hl) \] \[ 960 = 2(lb + bh + hl) \] Dividing both sides by 2: \[ lb + bh + hl = 480 \quad \text{(Equation 3)} \] ### Step 5: Calculate the surface area The surface area \( S \) of a cuboid is given by: \[ S = 2(lb + bh + hl) \] Substituting Equation 3 into this formula: \[ S = 2 \times 480 = 960 \, \text{cm}^2 \] ### Final Answer The surface area of the cuboid is \( 960 \, \text{cm}^2 \). ---
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