Home
Class 9
MATHS
A balloon is connected to a meteorologic...

A balloon is connected to a meteorological station by a cable of length 200 m inclined to the horizontal at an angle of 60°. Determine the height of the balloon from the ground. Assume that there is no slack in a cable. [Take `sqrt3 = 1.73)`.

Text Solution

AI Generated Solution

The correct Answer is:
To determine the height of the balloon from the ground, we can use trigonometry. Here’s a step-by-step solution: ### Step 1: Understand the Problem We have a right triangle formed by the cable, the height of the balloon, and the horizontal distance from the meteorological station to the point directly below the balloon. The cable length is the hypotenuse, and the height of the balloon is the opposite side. ### Step 2: Identify the Given Values - Length of the cable (hypotenuse) = 200 m - Angle of inclination (angle with the horizontal) = 60° ### Step 3: Set Up the Trigonometric Relationship In a right triangle, we can use the sine function to relate the angle to the opposite side (height of the balloon) and the hypotenuse (length of the cable): \[ \sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} \] Here, \(\theta = 60^\circ\), opposite = height (h), and hypotenuse = 200 m. ### Step 4: Substitute the Values into the Equation \[ \sin(60^\circ) = \frac{h}{200} \] ### Step 5: Use the Value of \(\sin(60^\circ)\) The value of \(\sin(60^\circ)\) is \(\frac{\sqrt{3}}{2}\). Therefore, we can rewrite the equation as: \[ \frac{\sqrt{3}}{2} = \frac{h}{200} \] ### Step 6: Solve for h To find h, we can rearrange the equation: \[ h = 200 \times \frac{\sqrt{3}}{2} \] \[ h = 100\sqrt{3} \] ### Step 7: Substitute the Value of \(\sqrt{3}\) Given that \(\sqrt{3} \approx 1.73\): \[ h = 100 \times 1.73 = 173 \text{ m} \] ### Final Answer The height of the balloon from the ground is **173 meters**. ---
Promotional Banner

Topper's Solved these Questions

  • CHAPTERWISE REVISION (STAGE 3)

    ICSE|Exercise CO-ORDINATE GEOMETRY |6 Videos
  • CHAPTERWISE REVISION (STAGE 3)

    ICSE|Exercise GRAPHICAL SOLUTION|3 Videos
  • CHAPTERWISE REVISION (STAGE 3)

    ICSE|Exercise SOLIDS |6 Videos
  • CHAPTERWISE REVISION (STAGE 1)

    ICSE|Exercise Graphical solution |10 Videos
  • CIRCLE

    ICSE|Exercise EXERCISE 17(D)|12 Videos

Similar Questions

Explore conceptually related problems

A balloon is connected to a meteorological ground station by a cable of length 215m inclined at 60o to the horizontal. Determine the height of the balloon from the ground. Assume that there is no slack in the cable.

A kite is flying at a height of 60 m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 60^@ . Find the length of the string, assuming that there is no slack in the string.

A kite is flying at a height of 60m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 60^@ . Find the length of the string assuming that there is no slack in the string.

From the ground, a projectile is fired at an angle of 60 degree to the horizontal with a speed of 20" m s"^(-1) The horizontal range of the projectile is

A ball is dropped from a balloon going up at a speed of 7 m/s. If the balloon was at a height 60 m at the time of dropping the ball, how long will the ball take in reaching the ground?

A balloon starts rising from the ground with an acceleration of 1.25 m//s^(2) . A stone is released from the balloon after 10s. Determine (1) maximum height of ston from ground (2) time taken by stone to reach the ground

From the top of a 7m high building, the angle of elevation of the top of a cable tower is 60o and the angle of depression of its foot is 45o . Determine the height of the tower.

The angles of depression of the and bottom of a 50 m high building from the top of a tower are 45^(@)" and "60^(@) respectively. Find the height of the tower and the horixontal distance between the tower and the building. (Use sqrt3=1.73 ).

A kite is flying at a height of 75 metres from the ground level, attached to a string inclined at 60^@ to the horizontal. Find the length of the string to the nearest metre.

A ball is projected form ground with a speed of 20 ms^(-1) at an angle of 45∘ with horizontal.There is a wall of 25m height at a distance of 10m from the projection point. The ball will hit the wall at a height.

ICSE-CHAPTERWISE REVISION (STAGE 3) -TRIGONOMETRY
  1. In an isosceles triangle ABC. AB = BC = 10 cm and BC = 18 cm . Fi...

    Text Solution

    |

  2. In Triangle ABC, AD is perpendicular to BC, tan B "" = (3)/(4) tan ...

    Text Solution

    |

  3. A balloon is connected to a meteorological station by a cable of lengt...

    Text Solution

    |

  4. ABCD is an isosceles trapezium with AB parallel to DC, AD = BC = 12 cm...

    Text Solution

    |

  5. ABCD is an isosceles trapezium with AB parallel to DC, AD = BC = 12 cm...

    Text Solution

    |

  6. If A,B,C are angles of a triangle, prove that "tan "(B+C)/(2)="cot"...

    Text Solution

    |

  7. If A + B = 90 ^(@) , show that : cos A = sqrt(( cos A)/(sin B) -...

    Text Solution

    |

  8. Prove that : tan (55^(@) + x) = cot (35^(@) - x)

    Text Solution

    |

  9. Prove that : sec (70^(@) - 0) = cosec (20^(@) + 0)

    Text Solution

    |

  10. Prove that : Sin( 28 ^(@) +A) = cos ( 62 ^(@) - A)

    Text Solution

    |

  11. Prove that : (sinthetacos(90^0-theta)costheta)/(sin(90^0-theta))+(cost...

    Text Solution

    |

  12. If tan2theta=cot(theta+6^@) , where 2theta and theta+6^@ are acute a...

    Text Solution

    |

  13. If in Delta ABC , angle C = 90 ^(@) , prove that : sqrt((1-sin A)...

    Text Solution

    |

  14. Solve for theta (0^(@) lt theta lt 90 ^(@)) 2 sin ^(2) theta = (...

    Text Solution

    |

  15. Solve for theta ( 0 ^(@) lt theta lt 90^(@)) 2 cos 3 theta= 1

    Text Solution

    |

  16. If cosec theta = sqrt2 , find the value of : (1)/(tan A ) +( sin ...

    Text Solution

    |

  17. If 2 cos theta = sqrt3. prove that : 3 sin theta - 4 sin ^(3) thet...

    Text Solution

    |

  18. Given A is an acute angle and 13 sin A = 5 , evaluate : ( 5 sin A...

    Text Solution

    |

  19. Prove that cos 30 ^(@) = (sqrt3)/(2)

    Text Solution

    |

  20. If sin theta = cos theta find the value of : 3 tan ^(2) theta+ 2 si...

    Text Solution

    |