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Find the equation of the line whose x-intercept is 8 and y-intercept is -12.

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To find the equation of the line whose x-intercept is 8 and y-intercept is -12, we can follow these steps: ### Step 1: Identify the intercepts The x-intercept is the point where the line crosses the x-axis, which is given as (8, 0). The y-intercept is the point where the line crosses the y-axis, which is given as (0, -12). ### Step 2: Use the two-point form of the equation of a line The two points we have are: - Point A (8, 0) - x-intercept - Point B (0, -12) - y-intercept The formula for the equation of a line passing through two points (x1, y1) and (x2, y2) is: \[ y - y_1 = \frac{y_2 - y_1}{x_2 - x_1} (x - x_1) \] ### Step 3: Substitute the points into the formula Here, we can let: - \( (x_1, y_1) = (8, 0) \) - \( (x_2, y_2) = (0, -12) \) Substituting these values into the formula gives: \[ y - 0 = \frac{-12 - 0}{0 - 8} (x - 8) \] ### Step 4: Simplify the equation This simplifies to: \[ y = \frac{-12}{-8} (x - 8) \] \[ y = \frac{12}{8} (x - 8) \] \[ y = \frac{3}{2} (x - 8) \] ### Step 5: Distribute and rearrange Distributing the right side: \[ y = \frac{3}{2}x - \frac{3}{2} \times 8 \] \[ y = \frac{3}{2}x - 12 \] ### Step 6: Rearranging to standard form To convert this to standard form \( Ax + By + C = 0 \): \[ \frac{3}{2}x - y - 12 = 0 \] Multiplying through by 2 to eliminate the fraction: \[ 3x - 2y - 24 = 0 \] Rearranging gives: \[ 3x - 2y = 24 \] ### Final Equation Thus, the equation of the line is: \[ 3x - 2y = 24 \] ---
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ICSE-EQUATION OF A LINE-EXERCISE 14(E)
  1. Find the equation of the line whose x-intercept is 8 and y-intercept i...

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  2. Point P divides the line segment joining the points A (8,0) and B (16,...

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  3. The line segment joining the points A (3,-4) and B (-2, 1) is divided ...

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  4. A line 5x + 3y + 15 = 0 meets y-axis at point P. Find the co-ordinates...

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  5. Find the value of k for which the lines kx - 5y + 4 = 0 and 5x – 2y +...

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  6. A straight line passes through the points P(-1, 4) and Q(5,-2). It int...

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  7. A straight line passes through the points P(-1, 4) and Q(5,-2). It int...

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  8. A straight line passes through the points P(-1, 4) and Q(5,-2). It int...

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  9. (1, 5) and (-3, -1) are the co-ordinates of vertices A and C respectiv...

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  10. Show that A (3, 2), B (6, -2) and C (2, -5) can be the vertices of a s...

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  11. Show that A (3, 2), B (6, -2) and C (2, -5) can be the vertices of a s...

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  12. A line through origin meets the line x = 3y + 2 at right angles at poi...

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  13. A straight line passes through the point (3, 2) and the portion of thi...

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  14. Find the equation of the line passing through the point of intersectio...

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  15. Find the equation of the line which is perpendicular to the line x/a -...

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  16. O (0, 0), A (3, 5) and B (-5, -3) are the vertices of triangle OAB. Fi...

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  17. O (0, 0), A (3, 5) and B (-5, -3) are the vertices of triangle OAB. Fi...

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  18. Determine whether the line through points (-2, 3) and (4, 1) is perpen...

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  19. Given a straight line x cos 30^@ + y sin 30^@ = 2. Determine the equat...

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  20. Find the value of k such that the line (k-2)x+(k+3)y-5=0 perpendi...

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  21. Find the value of k such that the line (k-2)x+(k+3)y-5=0 is para...

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