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In the half yearly examination of class ...

In the half yearly examination of class IX of a school, the mean marks scored by the boys is 52 and the mean marks scored by the girls is 48. If on the whole, the mean marks of the calss is 50.5, find the ratio of the number of boys to the number of girls in the class.

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To solve the problem, we will use the formula for the mean and the information provided about the mean marks of boys, girls, and the overall class. ### Step-by-Step Solution: 1. **Let the number of boys and girls be defined:** - Let the number of boys be \( m \). - Let the number of girls be \( n \). 2. **Write down the mean marks for boys and girls:** - The mean marks scored by boys is 52. - The mean marks scored by girls is 48. 3. **Calculate the total marks for boys and girls:** - Total marks scored by boys = \( 52m \) (since mean = total marks/number of students). - Total marks scored by girls = \( 48n \). 4. **Write down the overall mean marks for the class:** - The overall mean marks of the class is given as 50.5. - Therefore, the total marks for the whole class can be expressed as: \[ \text{Total Marks} = \text{Total Marks of Boys} + \text{Total Marks of Girls} = 52m + 48n \] - The total number of students in the class is \( m + n \). 5. **Set up the equation using the overall mean:** - According to the formula for mean: \[ \text{Mean} = \frac{\text{Total Marks}}{\text{Total Number of Students}} \] - Substituting the values we have: \[ 50.5 = \frac{52m + 48n}{m + n} \] 6. **Cross-multiply to eliminate the fraction:** \[ 50.5(m + n) = 52m + 48n \] 7. **Expand and rearrange the equation:** \[ 50.5m + 50.5n = 52m + 48n \] \[ 50.5m + 50.5n - 52m - 48n = 0 \] \[ -1.5m + 2.5n = 0 \] 8. **Rearranging gives us:** \[ 2.5n = 1.5m \] \[ \frac{m}{n} = \frac{2.5}{1.5} = \frac{5}{3} \] 9. **Finding the ratio of boys to girls:** - Therefore, the ratio of the number of boys to the number of girls is: \[ \text{Ratio of boys to girls} = \frac{m}{n} = \frac{5}{3} \] ### Final Answer: The ratio of the number of boys to the number of girls in the class is \( 5:3 \).
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ICSE-MEASURES OF CENTRAL TENDENCY (MEAN, MEDIAN, QUARTILES AND MODE)-EXERCISE 24 (E)
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  7. The marks of 20 students in a test were as follows, 2,6,8,9,10,11,11...

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  8. If PQR is an equilateral triangle and PX ⊥ QR, find the value of PX^2.

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  9. The sides AB and AC and the perimeter P, of ∆ABC are respectively thre...

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  10. The distribution given below, shows the marks obtained by 25 students ...

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  11. The mean of the following distribution is 52 and the frequency of clas...

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  12. In the figure, EF || AC, BC = 10 cm, AB = 13 cm and EC = 2 cm, find AF

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  13. A Mathematics aptitude test of 50 students was recorded as follows: ...

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  14. In the figure ABC and DBC are two right triangles. Prove that AP × PC ...

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  15. Marks obtaind by 40 students in a short assessment is given below, whe...

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  16. Find the mode and the median of the following data 13, 16, 12, 14, 19...

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  17. The median of the following observation 11, 12, 14, (x - 2), (x + 4), ...

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  18. The numbers 6, 8, 10 ,12, 13, and x are arranged in an ascending order...

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  19. (Use a graph paper for this question). The daily pocket expenses of 20...

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  20. In the given figure, QA ⊥ AB and PB ⊥ AB. If AO = 20 cm, BO = 12 cm, P...

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  21. The mean of the following numbers is 68. Find the value of 'x'. 45, ...

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