Home
Class 8
MATHS
Add : 5a + 3b, a - 2b, 3a + 5b...

Add :
`5a + 3b, a - 2b, 3a + 5b`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of adding the algebraic expressions \(5a + 3b\), \(a - 2b\), and \(3a + 5b\), we can follow these steps: ### Step 1: Write down the expressions We start with the three expressions: \[ 5a + 3b, \quad a - 2b, \quad 3a + 5b \] ### Step 2: Combine like terms Next, we group the like terms together. The terms with \(a\) are \(5a\), \(a\), and \(3a\). The terms with \(b\) are \(3b\), \(-2b\), and \(5b\). So we can rewrite the expression as: \[ (5a + a + 3a) + (3b - 2b + 5b) \] ### Step 3: Simplify the \(a\) terms Now, we simplify the \(a\) terms: \[ 5a + a + 3a = 5a + 1a + 3a = (5 + 1 + 3)a = 9a \] ### Step 4: Simplify the \(b\) terms Next, we simplify the \(b\) terms: \[ 3b - 2b + 5b = (3 - 2 + 5)b = 6b \] ### Step 5: Combine the results Now we combine the simplified \(a\) and \(b\) terms: \[ 9a + 6b \] ### Final Answer The final result after adding the expressions is: \[ \boxed{9a + 6b} \] ---
Promotional Banner

Topper's Solved these Questions

  • ALGEBRAIC EXPRESSIONS

    ICSE|Exercise Exercise 11(C)|45 Videos
  • ALGEBRAIC EXPRESSIONS

    ICSE|Exercise Exercise 11 (D)|21 Videos
  • ALGEBRAIC EXPRESSIONS

    ICSE|Exercise Exercise 11 (A)|30 Videos
  • AREA OF A TRAPEZIUM AND A POLYGON

    ICSE|Exercise EXERCISE 20(D)|21 Videos

Similar Questions

Explore conceptually related problems

Add : 6- 3a + b , a - 7-6b and 3b + 2- a.

Add : 3b - 7c + 10, 5c - 2b - 15, 15 + 12c + b

Add : a - 3b + 3, 2a + 5 - 3c, 6c - 15 + 6b

Add the following algebraic expressions : 2a - 3b + 4c , -3a + 2b - 5c , 7a - c and 3b + 6c

Add the expressions : 3a - 2b + 5c and 4a + 7b - 9c

Find the sum of the following algebraic expressions : 3a - 4b + 5c , 2a + 3b - 6c , - 5a + 8b + 7c

Given, (a)/(b) = (c)/(d) , prove that : (3a - 5b)/(3a + 5b) = (3c - 5d)/(3c + 5d)

Add the following expressions using horizontal method : 2a + 3b +4c and 3a+ 4b + 2c

4 a 2 b 3 x 3a b 2 x 5 a 3 b is equal to: (a) 60 a 3 b 5 (b) 60 a 6 b 5 (c) 60 a 6 b 6 (d) a 6 b 5

What must be added to 5a , -3b + 2c " to get " 3a - 4b + 7c ?