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Find the equation of the circle with cen...

Find the equation of the circle with centre (2,2) and passing through the point(4,5).

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Let .C. be the centre and .P. be the point .(4,5). .therefore. Radius .(r)=CP doteq sqrt(4-2)^2+(5-2)^2=sqrt2^2+3^2=sqrt4+9=sqrt13 rarr r^2=13. .therefore. Equation of the required (circ)le is .(x-2)^2+(y-2)^2=13. .x^2-4 x+4+y^2-4 y+4=13 , x^2 div y^2-4 x-4 y-5=0.
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