An equilateral triangle is inscribed in the parabola `y^2=4 a x`, where one vertex is at the vertex of the parabola. Find the length of the side of the triangle.

An equilateral triangle is inscribed in the parabola y^2 =4ax whose one vertex is at the vertex of the parabola if 1 cms is the side of the equilateral triangle prove that the length of each altitude of the triangle is (1sqrt3)/2 cms

An equilateral triangle is inscribed in the parabola y^2 =4ax whose one vertex is at the vertex of the parabola Show that side of the triangle=8sqrt3 a cms

An equilateral triangle is inscribed in the parabola y^(2) = 4x . If a vertex of the triangle is at the vertex of the parabola, then the length of side of the triangle is a) sqrt(3) b) 8 sqrt(3) c) 4 sqrt(3) d) 3 sqrt(3)

An equilateral triangle with side 1c.m is inscribed in the parabola y^2 =4ax whose one vertex is at the vertex of the parabola Prove that [(1sqrt3)/2, 1/2] is a point on the parabola

Consider the parabola y^2=12x Find the length of the latus rectum.

A 50 centimetre long rod is to be cut into two pieces, one of which is to be bent to form a square and other is to be bent to form an equilateral triangle. The length of a side of the equilateral is twice the length of the side of a square. Find the length of the side of a square and equilateral triangle.

The vertex of the parabola y=(x-2)(x-8)+7 is

Find the length of the latus rectum of the parabola x^2=-8y

The line x-1=0 is the directrix of a parabola, y^2=kx then Find the vertex, focus,axis of parabola and length of latus rectum of the parabola.