Find the equation of the circle whose centre is at `(-3,-2)` and radius equal to `7`.

Explanation

Here .(h, k)=(-3,-2). and .r=7.
using .(x-h)^2+(y-k)^2=r^2., the equation of the (circ)le is
.(x+3)^2+(y+2)^2=(7)^2.
.rarr x^2+y^2+6 x+4 y-36=0.