A fair coin with 1 marked on one face and 6 on the other and a fair die are
both tossed.find the probability that the sum of numbers that turn up 12.

Explanation

therefore. The number of outcomes are .(1.1)(1,2)(1,3)(1,4),(1,5),(1,6)(6,1),(6,2),(6,3),(6,4),(6,5).
.(6,6).
i) The favourable outcomes are .(1,2). Number of total outcomes 12 and:number of favourable outcomes 1 .i r_3.
ii) .Th_r.. favourable outcomes are .(6,6).. Plus One Mathematics
.therefore. Probability of getting sum .12=1/12.