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Events E and F are such that P(not E or not F)=`0.25`, state whether `E` and `F` are mutually exclusive.

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P(. not .E. or .not F)=P(E^(prime) uu F^(prime))=P(E nn F)^(prime). Therefore, .P(E nn F)^(prime)=0.25 rarr 1-P(E nn F)=0.25 rarr P(E nn F)=1-0.25=0.75. Since .P(E nn F) neq phi, E. and .F. are not mutually exclusive.
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V PUBLICATION-PROBABILITY-QUESTION BANK
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