The probability that a student will pass the final examination. in both English and Hindi is '0.5' and the probability of passing neither is '0.1 .' If the probability of passing the English examination is '0.75', what is the probability of passing the Hindi examination. Let probability: of passing English be 'E' and probability of passing Hindibe 'H'.

Explanation

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therefore P(E nn H)=0.5
P(E^(prime) nn dotH^(prime))=P(E uu H)^(prime)=1-P(E uu H)=0.1 , therefore P(E uu H)=1-0.1=0.9 t
P(E)=0.75
P(E uu H)=P(E)+P(H)-P(E nn H)
P(H)=P(E uu H)-P(E)+P(E nn H)=0.9-0.75+0.5=1.4-0.75=0.65
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