A particle has an initial velocity of `9 m//s^(2) ` due east and a constant acceleration of 2 due west. The distance covered by the particle in the fifth second of its motion is :

Options

A. `0`
B. `0.25m`
C. `0.5m`
D. `7m`

Answer

C

Explanation

A particle………
Distance travelled `= |S_(3-3.5)|+|S_(3.5-4)|`
`|(1+0)/(2)xx0.5|+|(0+(-1))/(2)xx0.5|=0.25+0.25`
`= 0.5m`.