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If a stone is relased from a balloon mov...

If a stone is relased from a balloon moving upwards with certain velocity `v_(0)` at certain height above earth's surface then velocity time curve of stone's motion can be best represented by : (g = constant)

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The correct Answer is:
To solve the problem, we need to analyze the motion of the stone after it is released from the balloon. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the Initial Conditions When the stone is released from the balloon, it has an initial upward velocity `v_0` (the same velocity as the balloon). **Hint:** Remember that the stone will initially continue moving in the direction it was moving at the moment of release. ### Step 2: Identify the Forces Acting on the Stone Once the stone is released, the only force acting on it is gravity, which pulls it downward with an acceleration `g`. **Hint:** The stone is no longer influenced by the balloon's motion after release; it is now in free fall. ### Step 3: Analyze the Motion of the Stone The stone will first move upward (since it has an initial upward velocity `v_0`), but as it ascends, the gravitational force will decelerate it until it reaches a maximum height where its velocity becomes zero. **Hint:** The stone's upward motion will continue until the gravitational force counteracts its initial velocity. ### Step 4: Determine the Velocity-Time Relationship 1. **Upward Motion:** The stone will move upward until it reaches its maximum height. During this phase, its velocity decreases from `v_0` to `0`. 2. **Downward Motion:** After reaching the maximum height, the stone will start falling back down, gaining speed in the downward direction (negative velocity). **Hint:** The velocity-time graph will show a decrease in velocity to zero and then a negative velocity as the stone falls back down. ### Step 5: Sketch the Velocity-Time Curve The velocity-time curve will start at `v_0`, decrease linearly to `0` (at the maximum height), and then continue to decrease into negative values as the stone falls back down. **Hint:** Since the acceleration due to gravity is constant, the velocity-time graph will be a straight line with a negative slope after the stone reaches its maximum height. ### Conclusion Based on the analysis, the velocity-time curve of the stone's motion can be best represented by option 2, which shows a positive initial velocity that decreases to zero and then becomes negative. **Final Answer:** The correct representation of the velocity-time curve is option 2.

To solve the problem, we need to analyze the motion of the stone after it is released from the balloon. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the Initial Conditions When the stone is released from the balloon, it has an initial upward velocity `v_0` (the same velocity as the balloon). **Hint:** Remember that the stone will initially continue moving in the direction it was moving at the moment of release. ### Step 2: Identify the Forces Acting on the Stone ...
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