The velocity displacement graph of a particle is shown in figure. The acceleration of the particle when `x = 0` is.

Options

A. `(1)/(sqrt(3))m//s^(2)`
B. `-(2)/(sqrt(3))m//s^(2)`
C. `(2)/(3)m//s^(2)`
D. None of the above

Answer

B

Explanation

The velocity …………… ltbRrgt From figure `-tan 30^(@)= (dv)/(dx)`
`:'` acceleration `a = v(dv)/(dx)`
`a = -v tan30^(@)` ltbtgt `at x = 0, v = 2 m//s` (from figure)
`so a = -2 tan 30^(@)`
`a = -(2)/(sqrt(3))m//s^(2)`