The acceleration of block 'C' is equal to `(g)/(12)m//s^(2)` where g is gravitational acceleratio. Acceleration of 'A' is equal to `(10g)/(x)m//s^(2)` then fill the value of x. All surface are smooth and pulleys are light. `(Take g = 10 m//s^(2))`

Options

A. `5`
B. `20`
C. `30`
D. `50`

Answer

C

Explanation

The acceleration ………….
`a = (b+c)/(2), b+c = 2a`
`2T = 10a`
`4g sin 30^(@)-T = 4c`
`T = 2g - (4g)/(12) = (5g)/(3)`
then `a = (2T)/(10) = (10g)/(3xx10) = (g)/(3)`