A block of mass m is connected to a spring of force constant k. Initially the block is at rest and the spring has natural length. A constant force F is applied horizontally towards right. The maximum speed of the block will be (there is no friction between block and the surface)

Answer

6

Explanation

A block of ………………
For maximum speed,
`(dv)/(dt) = 0 implies a = 0`
If at maximum speed, elongation is x, then
`F = kx implies x = (F)/(k)`
Now, by WET,
`-(1)/(2)kx^(2)+Fx=(1)/(2)mv^(2)`
`:. V = (F)/(sqrt(mk))=6 m//s`