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If a particle with a = kv^(2) and initia...

If a particle with `a = kv^(2)` and initial velocity is u then velocity after S displacement. Here `k` is a constant

A

`ue^(ks)`

B

`2ue^(ks)`

C

`ue^(2ks)`

D

`2ue^(2ks)`

Text Solution

Verified by Experts

The correct Answer is:
A
If a particle …………..
`a = (dV)/(dt)`
`v(dv)/(ds) = kv^(2)`
`int(dv)/(v)=k int ds`
`ln v = ks+c`
at `s = 0`, `v = u`
`implies lnv = ks + lnu`
`implies ln (V)/(u)= ks implies v = ue^(ks)`
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