A point moves in x-y plane according to the law `x=4 sin 6t and y=4 (1- cos 6t)`. The distance travelled by the particle in 4 s is (x and y are in metre)

Options

A. `96m`
B. `45m`
C. `24m`
D. `108m`

Answer

A

Explanation

A particle ……………
Distance `= sqrt((dx)^(2)+(dy)^(2))`
`= sqrt(((dx)/(dt))^(2)+((dy)/(dt))^(2))dt`
`= sqrt((24sin6t)^(2)+(24cos6t)^(2))dt = 24int_(0)^(4)dt = 96 m`