A uniform chain of length L and mass M is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, work required to pull the hanging part on to the table is

Options

A. `MgL`
B. `MgL//3`
C. `MgL//9`
D. `MgL//18`

Answer

D

Explanation

A uniform …………..

`W= (MgL)/(2n^(2))=(MgL)/(2(3)^(2)) = (MgL)/(18) (n = 3 given)`