A uniform disc of mass m and radius `r` rolls without slipping along a horizontal surface and ramp, as shown above. The disk has an initial velocity of `upsilon` . What is the maximum height h to which the center of mass of the disc rises ?

Options

A. `h = (upsilon^(2))/(2g)`
B. `h = (3upsilon^(2))/(4g)`
C. `h = (upsilon^(2))/(g)`
D. `h = (3upsilon^(2))/(2g)`

Answer

B

Explanation

A uniform disc ……………
`(3)/(4)mv^(2)= mgh implies h = (3v^(2))/(4g)`