Sinusoidal waves 5.00 cm in amplitude are to be transmitted along a string having a linear mass density equal to `4.00xx10^-2 kg//m`.If the source can deliver a average power of 90 W and the string is under a tension of 100 N, then the highest frequency at which the source can operate is (take `pi^2=10`):

Options

A. `45.3Hz`
B. `50Hz`
C. `30Hz`
D. `62.3Hz`

Answer

C

Explanation

Sinusodial waves …………..
`(C )P = (1)/(2) mu omega^(2) A^(2)V` using `V = sqrt((T)/(mu))`
`P = (1)/(2)omega^(2)A^(2) sqrt(T mu)`
`omega = sqrt((2P)/(A^(2)sqrt(T mu))) f = (omega)/(2pi) = (1)/(2pi) sqrt((2P)/(A^(2)sqrt(T mu)))`
using data `f = 30 Hz`.