A particle is projected horizontally from a tower with velocity u towards east. Wind provides constant horizontal acceleration `(g)/(2)` towards west. If particle strikes the ground vertically the then :

Options

A. Height of toward is `(2u^(2))/(g)`
B. The speed with which particle strikes ground is `2u`
C. Work done by wind force `(1)/(2)mu^(2)`
D. Particle3 strikes the ground after time `t = 2u//g`

Answer

A, B, D

Explanation

A particle …………..

in horizontal direction
`0=u-g//2t`
`t = 2u//g`
in vertical direction
`v = u+at`
`v=0+g. (2u)/(g)=2u`
`h=0+(1)/(2)g((2u)/(g))^(2) = (2u^(2))/(g)`