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Wedge of 10 kg is free to move on horizo...

Wedge of 10 kg is free to move on horizontal surface. At the given instant. Acceleration of wedge is (string and pulleys are ideal)

A

`2m//s^(2)` towards right

B

`2 m//s^(2)` towards left

C

`1 m//s^(2)` toeards left

D

`1 m//s^(2)` toward right

Text Solution

Verified by Experts

The correct Answer is:
D

Wedge of …………..
`FBD` of wedge

`T = F = 50 N`
`F cos 37^(@) - T cos53^(@) = 10.a`
`implies a =1 m//s^(2)`
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