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The total energy of the body executing S...

The total energy of the body executing S.H.M. is E. Then the kinetic energy when the displacement is half of the amplitude is

A

`(E )/(2)`

B

`(E )/(4)`

C

`(3E)/(4)`

D

`(sqrt(3))/(4)E`

Text Solution

Verified by Experts

The correct Answer is:
C
The total …………..
kinetic energy `=(1)/(2)m omega^(2)(a^(2)-x^(2))`
kinetic energy `= (1)/(2) ((3)/(4)m omega^(2)a^(2)) = (3E)/(4)`
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