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In adiabatic container with adiabatic pi...

In adiabatic container with adiabatic piston contains `4gm N_(2)` gas and `0.8 gm` He gas are separated by a weakly conducting light partition. Both piston and partition are free ro move. Initial temperature of `N_(2)` and He gases are `'3 T_(0)'` and `'T_(0)'` respectively. Initially system is at Rest and in equilibrium. Final temperature of the gas is.

A

`2T_(0)`

B

`(3T_(0))/(2)`

C

`(7T_(0))/(4)`

D

`(5T_(0))/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
In adiabatic …………..
`(4)/(28) ((7R)/(2))(3T_(0)-T) = ((0.8))/(4) ((5R)/(2))(T-T_(0))`
`T = 2T_(0)`
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