A body is thrown with a velocity of 9.8 m/s making an angle of `30^(@)` with the horizontal. It will hit the ground after a time

Answer

8

Explanation

A trolley is ………….
Velocity of bullet with respect to ground
`= 40 hati + 40 hat j + 50 hatk`
Time of fight `= (2xx50)/(10) = 10 sec`
Range of centre of mass
`= (2xx40sqrt(2)xx50)/(10)=400sqrt(2)m`
coordinate centre of mass after `10 sec = (500, 400, 0)`
One of the particle will fall on trolley
Position of trolley at the end of `10 sec`.
`= (200, 0, 0)`
Position of other partiolo = `(800, 800, 0)`
distance `= 800 sqrt(2)m implies M = 8`