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A projectile is given an initial velocit...

A projectile is given an initial velocity of `(hati+2hatj) m//s,` where `hati` is along the ground and `hatj` is along the vertical. If `g = 10 m//s^(2),` the equation of its trajectory is:

A

`3` sec

B

`2` sec

C

`5` sec

D

`4` sec

Text Solution

Verified by Experts

The correct Answer is:
A, D
Along `x-` direction `v_(X) = u_(X) + a_(X)t`

`6cosalpha = sqrt(11) rArr cos alpha = (sqrt(11))/(6), sinalpha = (5)/(6)`
Along `y-`direction `6sin = 35 - 10t`
`rArr t = 3 sec`.
Also `-6 sin theta = 35 - 10t`
`rArr t = 4 sec`
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