A particle A is projected with an initial velocity of `60 m//s` at an angle `30^@` to the horizontal. At the same time a second particle B is projected in opposite direction with initial speed of `50 m//s` from a point at a distance of 100 m from A. If the particles collide in air, find (a)the angle of projection `alpha` of particle B, (b) time when the collision takes place and (c) the distance of P from A, where collision occurs. `(g= 10 m//s^2)`

Options

A. time taken by fly to complete whole path is less then time taken by particle
B. acceleration of fly is zero
C. average velocity of both are same for whole journey
D. None of these

Answer

A

Explanation

`t = (distance)/(speed)`
Since, speed of fly `ge` speed of particle so time taken by fly is less.