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Let f(n)(theta) = sum(n=0)^(n) (1)/(4^(n...

Let `f_(n)(theta) = sum_(n=0)^(n) (1)/(4^(n))sin^(4)(2^(n)theta)`. Then which of the following alternative(s) is/are correct ?

A

`f_(2)((pi)/(4))=(pi)/(sqrt(2))`

B

`f_(3)((pi)/(8)) = (2 + sqrt(2))/(4)`

C

`f_(4)((3pi)/(2)) = 1`

D

`f_(5)(pi) = 0`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the function defined as: \[ f_n(\theta) = \sum_{n=0}^{n} \frac{1}{4^n} \sin^4(2^n \theta) \] ### Step 1: Rewrite the sine function We can rewrite \(\sin^4(x)\) using the identity \(\sin^4(x) = \left(\sin^2(x)\right)^2\) and the identity \(\sin^2(x) = 1 - \cos^2(x)\): \[ \sin^4(2^n \theta) = \left(\sin^2(2^n \theta)\right)^2 = \left(1 - \cos^2(2^n \theta)\right)^2 \] ### Step 2: Substitute into the summation Now, substituting this into our function: \[ f_n(\theta) = \sum_{n=0}^{n} \frac{1}{4^n} \left(1 - \cos^2(2^n \theta)\right)^2 \] ### Step 3: Expand the square Expanding the square gives: \[ (1 - \cos^2(2^n \theta))^2 = 1 - 2\cos^2(2^n \theta) + \cos^4(2^n \theta) \] ### Step 4: Substitute back into the summation Now substituting back into the summation: \[ f_n(\theta) = \sum_{n=0}^{n} \frac{1}{4^n} \left(1 - 2\cos^2(2^n \theta) + \cos^4(2^n \theta)\right) \] ### Step 5: Separate the summation We can separate the summation into three parts: \[ f_n(\theta) = \sum_{n=0}^{n} \frac{1}{4^n} - 2 \sum_{n=0}^{n} \frac{\cos^2(2^n \theta)}{4^n} + \sum_{n=0}^{n} \frac{\cos^4(2^n \theta)}{4^n} \] ### Step 6: Evaluate the first summation The first summation is a geometric series: \[ \sum_{n=0}^{n} \frac{1}{4^n} = \frac{1}{1 - \frac{1}{4}} = \frac{4}{3} \] ### Step 7: Evaluate the second summation The second summation can be evaluated using the known result for \(\sum_{n=0}^{\infty} x^n\): \[ \sum_{n=0}^{n} \frac{\cos^2(2^n \theta)}{4^n} \] This requires more advanced techniques, possibly involving generating functions or Fourier series, which may not yield a simple closed form. ### Step 8: Analyze the third summation The third summation involves \(\cos^4(2^n \theta)\), which can also be evaluated using identities or numerical methods. ### Step 9: Final expression Thus, the final expression for \(f_n(\theta)\) will depend on the evaluations of these summations. ### Conclusion To determine which alternatives are correct, we would need to evaluate \(f_n(\theta)\) for specific values of \(\theta\) and \(n\) based on the derived expression. ---

To solve the problem, we need to analyze the function defined as: \[ f_n(\theta) = \sum_{n=0}^{n} \frac{1}{4^n} \sin^4(2^n \theta) \] ### Step 1: Rewrite the sine function We can rewrite \(\sin^4(x)\) using the identity \(\sin^4(x) = \left(\sin^2(x)\right)^2\) and the identity \(\sin^2(x) = 1 - \cos^2(x)\): ...
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