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Druing P-N junction formation when the e...

Druing P-N junction formation when the electron and holes stops moving from P to N and N to P, then

A

there is increase in number of `+ve` and `-ve` ions at junction

B

there is increase in number of electrons at junction.

C

there is increase in number of holes at junction

D

there is increase in number of holes and electrons at junctions

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The correct Answer is:
To solve the question regarding what happens during the formation of a P-N junction when electrons and holes stop moving from P to N and N to P, we can break it down into a series of steps: ### Step-by-Step Solution: 1. **Understanding P-N Junction Formation**: - A P-N junction is formed by bringing together P-type and N-type semiconductors. The P-type semiconductor has an abundance of holes (positive charge carriers), while the N-type semiconductor has an abundance of electrons (negative charge carriers). 2. **Movement of Charge Carriers**: - When the P-N junction is formed, electrons from the N-side start to diffuse into the P-side where there are holes. Similarly, holes from the P-side diffuse into the N-side where there are electrons. 3. **Establishment of Equilibrium**: - As electrons move from the N-side to the P-side and holes move from the P-side to the N-side, they recombine at the junction, leading to a depletion region where there are no free charge carriers. 4. **Formation of Ionized Atoms**: - As the electrons and holes recombine, the P-side becomes positively charged due to the unneutralized acceptor ions, while the N-side becomes negatively charged due to the unneutralized donor ions. This creates an electric field at the junction. 5. **Stopping of Carrier Movement**: - Eventually, the electric field created by the ionized atoms opposes further movement of electrons and holes. This results in a state where the diffusion of charge carriers stops, and the system reaches equilibrium. 6. **Conclusion**: - Therefore, when the electrons and holes stop moving from P to N and N to P, it indicates that the depletion region has formed, and the junction is now stable with an electric field preventing further diffusion of charge carriers. ### Final Answer: When the electrons and holes stop moving from P to N and N to P during P-N junction formation, it results in the establishment of a depletion region with positive and negative ionized atoms at the junction, leading to equilibrium.
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RESONANCE ENGLISH-SEMICONDUCTORS-Exercise
  1. The drift current in a p-n junction is

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  2. For a reverse bias P-N junction-

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  3. Druing P-N junction formation when the electron and holes stops moving...

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  4. The value of barrier potential of P-N juntion in Ge is-

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  5. Region without free electrons and holes in a p-n junction is

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  6. One part of a device is connected with the negative terminal of a batt...

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  7. Potential barrier developed in a junction diode opposes the flow of

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  8. PN-junction diode works as a insulator, if connected

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  9. If the forward voltage in a diode is increased, the width of the deple...

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  10. The resistance of a reverse baised P-N junction diode is about-

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  11. In which case is the junction diode is not reverse bias-

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  12. If V(A) and V(B) denote the potentials of A and B, then the equivalent...

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  13. Avalanche breakdown is due to

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  14. If the two ends of a p-n junction are joined by a wire .

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  15. Symbolic representation of photodiode is

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  16. Symbol of zener diode-

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  17. Consider the following statements A and B and identify the correct ans...

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  18. Two junction diodes one of germanium (Ge) and other of sillicon (Si) a...

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  19. In a photodiode,the conductivity increases when the material is expose...

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  20. If the forward voltage in a semiconductor diode is chaged form 0.5 V t...

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