If the frequency of input alternating potential in n, then the ripple frequency of output potential of full wave rectifier will be-

Options

A. 2n
B. n
C. `(n)/(2)`
D. `(n)/(4)`

Answer

To solve the problem, we need to determine the ripple frequency of the output potential of a full wave rectifier when the input alternating potential has a frequency of \( n \).

### Step-by-Step Solution:

1. **Understand the Input Frequency**:
The input frequency of the alternating potential is given as \( n \).

2. **Identify the Function of a Full Wave Rectifier**:
A full wave rectifier converts the entire input AC waveform into a pulsating DC output. This means that it rectifies both halves of the AC cycle.

3. **Determine the Output Frequency**:
In a full wave rectifier, the output frequency is double the input frequency. This is because for every cycle of the input AC waveform, the output produces two pulses (one for each half of the AC cycle). Therefore, the output frequency \( f_{out} \) can be expressed as:
\[ f_{out} = 2 \times f_{in} \]
where \( f_{in} \) is the input frequency.

4. **Substituting the Given Frequency**:
Since the input frequency \( f_{in} \) is given as \( n \), we substitute this value into the equation:
\[ f_{out} = 2 \times n \]

5. **Conclusion**:
The ripple frequency of the output potential of the full wave rectifier is therefore \( 2n \).

### Final Answer:
The ripple frequency of the output potential of the full wave rectifier will be \( 2n \).

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