Which one of the following circuits shows correct biasing of a PNP transistor to operate in active region in the CE mode-

Options

A.
B.
C.
D.

Answer

To determine which circuit correctly biases a PNP transistor to operate in the active region in common emitter (CE) mode, we need to understand the biasing conditions required for a PNP transistor.

### Step-by-Step Solution:

1. **Understand PNP Transistor Biasing**:
- In a PNP transistor, the emitter must be at a higher potential than the base for the emitter-base junction to be forward biased.
- The collector must be at a lower potential than the base for the collector-base junction to be reverse biased.

2. **Identify the Biasing Conditions**:
- For the PNP transistor to operate in the active region:
- Emitter (E) > Base (B) (E is positive relative to B)
- Collector (C) < Base (B) (C is negative relative to B)

3. **Analyze the Given Options**:
- Check each circuit option to see if it satisfies the above conditions.
- **Option A**: Emitter is positive, Base is positive, Collector is negative. (Incorrect, Base should be negative)
- **Option B**: Emitter is positive, Base is negative, Collector is negative. (Correct, satisfies all conditions)
- **Option C**: Emitter is negative, Base is negative, Collector is positive. (Incorrect, Emitter should be positive)
- **Option D**: Emitter is positive, Base is negative, Collector is positive. (Incorrect, Collector should be negative)

4. **Conclusion**:
- The only option that satisfies the conditions for a PNP transistor to operate in the active region in common emitter mode is **Option B**.

### Final Answer:
**Option B** is the correct answer.

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