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NAND gate is-...

NAND gate is-

A

a basic gate

B

not a universal gate

C

a universal gate

D

a universal gate

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The correct Answer is:
### Step-by-Step Solution: 1. **Definition of NAND Gate**: The NAND gate is a digital logic gate that outputs false only when all its inputs are true. It is the inverse of the AND gate. 2. **Truth Table of NAND Gate**: The truth table for a NAND gate with two inputs (A and B) is as follows: - When A = 0, B = 0 → Output = 1 - When A = 0, B = 1 → Output = 1 - When A = 1, B = 0 → Output = 1 - When A = 1, B = 1 → Output = 0 Thus, the output can be summarized as: ``` A | B | Output 0 | 0 | 1 0 | 1 | 1 1 | 0 | 1 1 | 1 | 0 ``` 3. **Why is it called a Universal Gate?**: The NAND gate is termed a universal gate because it can be used to create any other type of logic gate, including AND, OR, and NOT gates. 4. **Implementation of AND Gate using NAND Gates**: - To create an AND gate using NAND gates, connect the outputs of a NAND gate back to its inputs. - For inputs A and B, the output of the first NAND gate is \( \overline{A \cdot B} \). - If we take this output and feed it into another NAND gate (with both inputs being the output of the first NAND gate), we get: \[ \text{Output} = \overline{\overline{A \cdot B}} = A \cdot B \] Thus, we have constructed an AND gate. 5. **Implementation of OR Gate using NAND Gates**: - To create an OR gate, first, invert both inputs using NAND gates. - Connect inputs A and B to two separate NAND gates to get \( \overline{A} \) and \( \overline{B} \). - Then, connect these outputs to another NAND gate: \[ \text{Output} = \overline{\overline{A} \cdot \overline{B}} = A + B \] Thus, we have constructed an OR gate. 6. **Implementation of NOT Gate using NAND Gates**: - To create a NOT gate, connect the input A to both inputs of a NAND gate: \[ \text{Output} = \overline{A \cdot A} = \overline{A} \] Thus, we have constructed a NOT gate. 7. **Conclusion**: Since the NAND gate can be used to construct NOT, AND, and OR gates, it is classified as a universal gate. ### Final Answer: The NAND gate is a universal gate because it can be used to implement NOT, AND, and OR gates. ---
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RESONANCE ENGLISH-SEMICONDUCTORS-Exercise
  1. The current gain for a transistor working as common base amplifier is ...

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  2. In an n-p-n transistor 10^10 electron enter the emitter in 10^(-6) s. ...

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  3. In the following common emitter configuration an npn transistor with c...

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  4. An n - p- n transistor is connected in common - emitter configurarati...

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  5. In an NPN transistor the values of base current and collector current ...

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  6. In a common emitter circuit, if V(CE) is changed by 0.2 V, then collec...

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  7. Which of the following statement is not true?

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  8. The symbolic representation of four logic gates are given below. The l...

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  9. The output of OR gate is 1 :-

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  10. Following diagram performs the logic function of-

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  11. The following truth table corresponds to the logic gate

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  12. NAND gate is-

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  13. The given truth table relates y to A and B. {:(A,B,Y),(0,0,1),(0,1,0...

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  14. In the given circuit as shown the two input waveform A and B are appli...

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  15. For the logic circuit shown the boolean relation is-

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  16. For the given combination of gates, if the logic states of inputs A,B,...

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  17. The boolean equation of NOR gate is-

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  18. According to de morgan's theorem-

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  19. What will be input of A and B for the Boolean expression bar((A+B)).ba...

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  20. The Boolean expression for the output Y of the logic operation shown i...

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