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In a common base mode of a transition ,...

In a common base mode of a transition , the collector current is `5.488 mA` for an emitter currect of `5.60 mA` . The value of the base current amplification factor `(beta)` will be

A

49

B

50

C

51

D

48

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The correct Answer is:
To find the base current amplification factor (β) in a common base mode of a transistor, we can follow these steps: ### Step 1: Identify the given values - Collector current (Ic) = 5.488 mA - Emitter current (Ie) = 5.60 mA ### Step 2: Calculate the base current (Ib) The base current can be calculated using the relationship: \[ I_b = I_e - I_c \] Substituting the values: \[ I_b = 5.60 \, \text{mA} - 5.488 \, \text{mA} \] \[ I_b = 0.112 \, \text{mA} \] ### Step 3: Calculate the base current amplification factor (β) The base current amplification factor (β) is defined as the ratio of the collector current (Ic) to the base current (Ib): \[ \beta = \frac{I_c}{I_b} \] Substituting the values: \[ \beta = \frac{5.488 \, \text{mA}}{0.112 \, \text{mA}} \] Calculating this gives: \[ \beta = 49 \] ### Final Answer The value of the base current amplification factor (β) is **49**. ---
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RESONANCE ENGLISH-SEMICONDUCTORS-Exercise 3
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