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Determine the work done by an ideal gas ...

Determine the work done by an ideal gas doing `1 rarr 4 rarr 3rarr 2 rarr 1`.
Given `P_(1) = 10^(5) Pa, P_(0) = 3 xx 10^(5) Pa, P_(3) = 4 xx 10^(5) Pa` and `V_(2) - V_(1) = 10 L`.

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The correct Answer is:
`750J`

for similar traingle `ABC` and `CDE`
`(V_(1)-V_(1))/(p_(0)-p_(1)) = (V_(4)-V_(3))/(p_(2)-p_(0)) rArr V_(4) - V_(3)`
`=((p_(2)-p_(0)))/((p_(0)-p_(1)))(V_(1)-V_(1)) = (10^(5)xx10)/(2xx10^(5)) =5litre`
Work done by gas in cycle
`W_(gas) = W_(ABC) +W_(CDE)`
`= (1)/(2) (V_(2)-V_(1)) (p_(0)-p_(1)) - (1)/(2) (V_(4)-V_(3)) (p_(2)-p_(0))`
`= (1)/(2) xx 10 xx 10^(-3) (2xx10^(6)) - (1)/(2) xx5 xx 10^(-3) (1xx10^(6)) = 750 J`
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