In given figure, gas is slowely heated for sometime. During the process, the increases in internal energy of the gas is `10J` and the piston is found to move out by `25cm`, then find the amount of heat supplied. The area of cross-section of cylinder `= 40cm^(2)` and atmospheric pressure `100 kPa`

Answer

`110J`

Explanation

`dQ = dU +dW, = dU = PdV = dU +Padx`
`= 10 xx 10^(5) xx 40 xx 10^(-4) xx 25 xx 10^(-2)`
`rArr 10 +10^(5) xx 10^(-4) xx 1000 xx 10^(-2)`
`= 10 +100 = 110J, :. dQ = 110J`