In the above question, if the work done on the system along the curved path 'ba' is `52J`, heta abosrbed is

Options

A. `- 140J`
B. `-172 J`
C. `140J`
D. `172 J`

Answer

To solve the problem step by step, we will follow the principles of thermodynamics, particularly focusing on the first law of thermodynamics. The first law states that the change in internal energy (ΔU) of a system is equal to the heat added to the system (Q) minus the work done by the system (W).

### Step-by-Step Solution:

1. **Identify the Given Values**:
- Work done on the system along the path 'BA' (W) = 52 J (since work is done on the system, we will consider it as negative in our calculations).
- Change in internal energy (ΔU) = -120 J (as calculated from the previous context).

2. **Apply the First Law of Thermodynamics**:
The first law can be expressed as:
\[ \Delta U = Q - W \]
Rearranging this gives:
\[ Q = \Delta U + W \]

3. **Substitute the Known Values**:
Substitute ΔU and W into the equation:
\[ Q = -120 J + (-52 J) \]
Note: Since work is done on the system, we take W as -52 J.

4. **Calculate Q**:
\[ Q = -120 J - 52 J = -172 J \]

5. **Interpret the Result**:
The negative sign indicates that the system has lost heat, meaning that heat was not absorbed but rather released.

### Final Answer:
The heat absorbed (Q) is **-172 J**.