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An ideal gas has an adiabatic exponent g...

An ideal gas has an adiabatic exponent `gamma`. In some process its molar heat capacity varies as `C = alpha//T`,where `alpha` is a constant Find :
(a) the work performed by one mole of the gas during its heating from the temperature `T_0` to the temperature `eta` times higher ,
(b) the equation of the process in the variables `p, V`.

A

`a ln eta`

B

`(1)/(aln eta)`

C

`aln eta -((eta-1)/(gamma-1))RT_(0)`

D

`alneta -(gamma-1)RT_(0)`

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The correct Answer is:
To solve the problem step by step, we will address both parts (a) and (b) separately. ### Part (a): Work performed by one mole of the gas during its heating 1. **Identify the given parameters**: - Molar heat capacity \( C = \frac{\alpha}{T} \) - Initial temperature \( T_0 \) - Final temperature \( T_f = \eta T_0 \) 2. **Write the expression for work done**: The work done \( W \) during the heating process can be expressed as: \[ W = \int_{T_0}^{\eta T_0} C \, dT \] 3. **Substitute the expression for \( C \)**: Substitute \( C = \frac{\alpha}{T} \) into the work equation: \[ W = \int_{T_0}^{\eta T_0} \frac{\alpha}{T} \, dT \] 4. **Factor out the constant \( \alpha \)**: Since \( \alpha \) is a constant, it can be factored out of the integral: \[ W = \alpha \int_{T_0}^{\eta T_0} \frac{1}{T} \, dT \] 5. **Evaluate the integral**: The integral of \( \frac{1}{T} \) is \( \ln T \): \[ W = \alpha \left[ \ln T \right]_{T_0}^{\eta T_0} \] 6. **Substitute the limits**: Substitute the limits into the evaluated integral: \[ W = \alpha \left( \ln(\eta T_0) - \ln(T_0) \right) \] 7. **Use properties of logarithms**: Simplify the expression using properties of logarithms: \[ W = \alpha \left( \ln \eta + \ln T_0 - \ln T_0 \right) = \alpha \ln \eta \] Thus, the work performed by one mole of the gas during its heating is: \[ \boxed{W = \alpha \ln \eta} \] ### Part (b): Equation of the process in the variables \( p \) and \( V \) 1. **Recall the adiabatic process equation**: For an adiabatic process, the relationship between pressure \( p \) and volume \( V \) is given by: \[ p V^\gamma = \text{constant} \] where \( \gamma \) is the adiabatic exponent. 2. **Express \( \gamma \)**: The adiabatic exponent \( \gamma \) is defined as: \[ \gamma = \frac{C_p}{C_v} \] where \( C_p \) is the molar heat capacity at constant pressure and \( C_v \) is the molar heat capacity at constant volume. 3. **Relate \( C \) to \( C_p \) and \( C_v \)**: In the context of the problem, since \( C \) varies as \( \frac{\alpha}{T} \), we can use the relationship of \( C \) with \( C_p \) and \( C_v \) to find \( \gamma \). 4. **Final equation**: The equation of the process in terms of \( p \) and \( V \) remains: \[ p V^\gamma = \text{constant} \] Thus, the equation of the process in the variables \( p \) and \( V \) is: \[ \boxed{p V^\gamma = \text{constant}} \]

To solve the problem step by step, we will address both parts (a) and (b) separately. ### Part (a): Work performed by one mole of the gas during its heating 1. **Identify the given parameters**: - Molar heat capacity \( C = \frac{\alpha}{T} \) - Initial temperature \( T_0 \) - Final temperature \( T_f = \eta T_0 \) ...
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