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A scientist says that the efficiency of ...

A scientist says that the efficiency of his heat engine which operates at source temperature `127^(@)C` and sink temperature `27^(@)C is 26%`, then

A

It is impossible

B

It is possible but less probable

C

It is quite probable

D

Data are incomplete

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AI Generated Solution

The correct Answer is:
To determine whether the scientist's claim about the efficiency of his heat engine is possible, we will follow these steps: ### Step 1: Convert the temperatures from Celsius to Kelvin The temperatures given are: - Source temperature, \( T_1 = 127^\circ C \) - Sink temperature, \( T_2 = 27^\circ C \) To convert these temperatures to Kelvin, we use the formula: \[ T(K) = T(°C) + 273 \] Calculating the temperatures: \[ T_1 = 127 + 273 = 400 \, K \] \[ T_2 = 27 + 273 = 300 \, K \] ### Step 2: Use the formula for efficiency The efficiency of a heat engine is given by the formula: \[ \eta = 1 - \frac{T_2}{T_1} \] Substituting the values we calculated: \[ \eta = 1 - \frac{300}{400} \] ### Step 3: Simplify the efficiency calculation Now we simplify the fraction: \[ \eta = 1 - 0.75 = 0.25 \] ### Step 4: Convert efficiency to percentage To express the efficiency as a percentage, we multiply by 100: \[ \eta = 0.25 \times 100 = 25\% \] ### Step 5: Compare with the scientist's claim The scientist claims that the efficiency of his heat engine is 26%. However, we calculated the maximum possible efficiency based on the temperatures provided to be 25%. ### Conclusion Since the calculated efficiency (25%) is less than the claimed efficiency (26%), it is impossible for the scientist's claim to be true. ### Final Answer The scientist's claim that the efficiency of his heat engine is 26% is **not possible**. ---

To determine whether the scientist's claim about the efficiency of his heat engine is possible, we will follow these steps: ### Step 1: Convert the temperatures from Celsius to Kelvin The temperatures given are: - Source temperature, \( T_1 = 127^\circ C \) - Sink temperature, \( T_2 = 27^\circ C \) To convert these temperatures to Kelvin, we use the formula: ...
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