In given figure, let DeltaU(1) and Delta...

In given figure, let `DeltaU_(1)` and `DeltaU_(2)` be change in internal energy in process `ABC` and `CDA` respectively. `DeltaQ` and `W` be the net heta given and net work done by the system in the process `ABC +CDA`, then

A

`DeltaU_(1) +DeltaU_(2) =0`

B

`DeltaU_(1) - DeltaU_(2) =0`

C

`DeltaQ - W = 0`

D

`DeltaQ +W =0`

Text Solution

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The correct Answer is:

A, C

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