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For the previous question, the accelerat...

For the previous question, the acceleration of the particle at any time `t` is :

A

`-0.8m//s^(2)`

B

`0.8m//s^(2)`

C

`-0.6m//s^(2)`

D

`0.5m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(ds)/(dt)=15-0.8t=7=v`
`8=0.8t,t=10`second.
`a=(d^(2)s)/(dt^(2))=-0.8m//s^(2)`
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