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The equation of motion of a projectile i...

The equation of motion of a projectile is `y = 12 x - (3)/(4) x^2`. The horizontal component of velocity is `3 ms^-1`. What is the range of the projectile ?

A

`36m`

B

`30.6m`

C

`16m`

D

`12.4m`

Text Solution

Verified by Experts

The correct Answer is:
C
`y=xtantheta(1-(x)/(R))y=(12x)(1-(x)/(16))`
`rArr `Range `=16m Ans.`
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Knowledge Check

  • The equations of motion of a projectile are given by x=36tm and 2y =96t-9.8t^(2)m . The angle of projection is

    A
    `sin^(-1)((4)/(5))`
    B
    `sin^(-1)((3)/(5))`
    C
    `sin^(-1)((4)/(3))`
    D
    `sin^(-1)((3)/(4))`

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