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A stone projected at angle theta with ho...

A stone projected at angle `theta` with horizontal from the roof of a tall building falls on the ground after three seconds. Two second after the projection it was again at the level of projection. Then the height of the building

A

`5m`

B

`25m`

C

`2m`

D

`15m`

Text Solution

Verified by Experts

The correct Answer is:
D

`2=(2u_(y))/(g)rArru_(y)=10m//s`

Now, `H=-u_(y)t+(1)/(2)g t^(2)`
`=-30+45=15m`.
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Knowledge Check

  • If a body is projected with an angle theta to the horizontal, then

    A
    its velocity is always perpendicular to its acceleration then
    B
    its velocity becomes zero at its maximum height.
    C
    its velocity makes zero angle with the horizontal at its maximum height.
    D
    the body just before hitting the ground, the direction of velocity coincides with the acceleration.
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