Two blocks A and B each of mass m are placed on a smooth horizontal surface. Two horizontal force F and 2F are applied on blocks A and B, respectively, as shown in fig. Block A does not slide on block B. Then then the normal reaction acting between the two blocks is (assume no friction between the blocks)

Options

A. `F`
B. `F//2`
C. `(F)/(sqrt(3))`
D. `3F`

Answer

D

Explanation

Acceleration of two mass system is `a=(F)/(2m)` leftward
`FBD` of block `A`
`N cos 60^(@)-F=ma=(mF)/(2m)` solving `N=3F`