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Two men of masses m and m//2 starts clim...

Two men of masses `m` and `m//2` starts climbing up on two masseless strings fixed at the ceiling with acceleration `g` and `g//2` respectively. The ratio of tensions in the two strings will be `:`

A

`2:1`

B

`4:1`

C

`4:3`

D

`8:3`

Text Solution

Verified by Experts

The correct Answer is:
D
FBD of man of mass `(m)`

`T_(1)=mg+mg`
`T_(1)=2mg`
`rArr T_(1):T_(2): : 8:3`
FBD of man of mass `(m//2)`

`T_(2)=(m)/(2)g+(m)/(2).(g)/(2)`
`T_(2)=(mg)/(2)[(3)/(2)]=(3mg)/(4)`
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