A particle of mass `1kg` moves from rest along a straight line due to acition of a force `F` which varies with the displacement `x` as shown in graph`- (` Use `(1)/(sqrt(2))=0.8 ` if needed `)`

Options

A. maximum `K.E.` of particle is `25J`
B. Total work done by froce on particle up to `x=6m` is `-5J`
C. There will beno power delivered by the particle at `x=3,5.3` and `6m`
D. None of these

Answer

A, B, C

Explanation

`(A)` Maximum kinetic energy at `x=3m`.
`(B) KE=` work done`=` area under the curve
`=10xx2+(1)/(2)xx1=25J`
`(C)W_(ret)=` area under the curve `=25-(1)?(2)xx3xx20=-5J`
`(D)` Power `P=vec(F).vec(v)`