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A uniform rod of length 75 cm is hinged ...

A uniform rod of length `75 cm` is hinged at one of its ends and is free to rotate in vertical plane. It is released from rest when rod is horizontal. When the rod becomes vertical, it is breaks at mid`-` point and lower part now moves freely. The distance of centre of lower part from hinge, when it again becomes vertical for the first time is `r`. Find the approximate value of `2r`.

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The correct Answer is:
5


`g=(pi)/(omega)=(pi)/(sqrt(40))sec. `
`x=v_(0)t`
`y=(1)/(2)g t^(2)`
`r=sqrt(x^(2)+(y+(3l)/(4))^(2))~= 2.5m.`
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