Wedge of `10 kg` is free to move on horizontal surface. At the given instant, acceleration of wedge is (string and pulleys are ideal)

Options

A. `2 m//s^(2)` towards right
B. `2 m//s^(2)` towards left
C. `1 m//2^(2)` towards left
D. `1 m//s^(2)` toward right

Answer

D

Explanation

FBD of wedge FBD :

`T = F = 50 N`
`F cos 37^(2)-T cos 53^(@) =10a`
`rArra =1 m//s_(2)`